ABC is an isosceles triangle with ab equals to AC draw a be perpendicular to BC and show that angle b=c
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Given :- AB = AC
To Prove :- angle B = angle C
Proof :-
In triangle ABE & triangle ACE
angle AEB = angle AEC ( since AE is perpendicular to BC)
AB = AC ( given )
AE = AE ( Common Side )
Thus, By RHS Congruence Rule
triangle ABE congruent to triangle ACE;
Therefore, angle B = angle C ( C.P.C.T)
Hence, Proved
To Prove :- angle B = angle C
Proof :-
In triangle ABE & triangle ACE
angle AEB = angle AEC ( since AE is perpendicular to BC)
AB = AC ( given )
AE = AE ( Common Side )
Thus, By RHS Congruence Rule
triangle ABE congruent to triangle ACE;
Therefore, angle B = angle C ( C.P.C.T)
Hence, Proved
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