ABC is right angled triangle in which <A=90° and ab=ac.show that <b=<c
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its just use of a theorem that tells when two lines of triangle are same than their corresponding angles are also same
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Hey,
Let Abc is right angle triangle
Then in ∆Abc
ab=ac (given)
Then we can say that <b=<c(corresponding side are equal)
Or,
Let <a=x then<b=x
So x°+x°+90°=180°(sum of all angle of triangle is180°) then
2x=90°
X=45°
<b=45°also <c=45°
Then we can say that <b=<c.
Let Abc is right angle triangle
Then in ∆Abc
ab=ac (given)
Then we can say that <b=<c(corresponding side are equal)
Or,
Let <a=x then<b=x
So x°+x°+90°=180°(sum of all angle of triangle is180°) then
2x=90°
X=45°
<b=45°also <c=45°
Then we can say that <b=<c.
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