ABC is triangle,right angled at C ,AC=7cm,find BC
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Incomplete qn!
Qn is ------> ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
Now,
Given,
AB = 25 cm, AC = 7 cm
We know,
Pythagoras Theorem!
(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2
(AB)^2 = (AC)^2 + (BC)^2
(25)^2 = (7)^2 + (BC)^2
625 = 49 + (BC)^2
625 - 49 = (BC)^2
576 = (BC)^2
√576 = BC
24 = BC
Hence the length of BC = 24 cm.
Qn is ------> ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
Now,
Given,
AB = 25 cm, AC = 7 cm
We know,
Pythagoras Theorem!
(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2
(AB)^2 = (AC)^2 + (BC)^2
(25)^2 = (7)^2 + (BC)^2
625 = 49 + (BC)^2
625 - 49 = (BC)^2
576 = (BC)^2
√576 = BC
24 = BC
Hence the length of BC = 24 cm.
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