Question

ΔABC~ΔLBN. In ΔABC, AB=5.1cm, ∠B=40°, BC=4.8 cm,AC/LN =4/7 .Construct ΔABC and ΔLBN.

Answer 1

Answer:

ΔABC & ΔLBN is constructed

Step-by-step explanation:

Step 1: Draw Line AB of length = 5.1 cm

Step 2 : Draw angle B = 40 deg using Protector

Step 3 : Draw line BC at angle drawn = 4.8 cm

Step 4 : join A & C using straight line

ΔABC is constructed

now ΔABC~ΔLBN

=> AB/LB = BC/BN = AC/LN = 4/7

=> BN = 4.8*7/4 = 8.4 cm

Extend BC till BN = 8.4 cm

now draw || (parallel line) to CA from point N

Extend BA to intersect line drawn from N at point L

ΔLBN is constructed

Answer 2

Step-by-step explanation:

hope this will help you