Math, asked by priya769, 1 year ago

ABC together do work in 6 hrs A alone do work in20 hrs B alone work in24 hrs in how much time did C work


priya769: hey friend
shokhrukhmirzo: (A+B+C)×t=Work t=6
A×20=B×24=Work A=1.2B
2.2A×6+6C=Work
13.2A+6C=20A
6C=6.8A
A=0.88C
20A=Work=20×0.88C Work=17.6h

Answers

Answered by rocky128
1
In how many days C can finish the remaining work? A. 16. B. 32. C. 64. D. 96 ... So, by the time C is left alone 1 - (124/ 300 + 80/300) = 96/300 of the work is left ...
Answered by shokhrukhmirzo
0
(A+B+C)×t=Work t=6
A×20=B×24=Work A=1.2B
2.2A×6+6C=Work
13.2A+6C=20A
6C=6.8A
A=0.88C
20A=Work=20×0.88C Work=17.6h
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