Question

ABCD in which AB=4.2cm, BC=4.5cm, CD=4 cm, OA=4.8cm and angle A =72°
please construct it and also write it's steps of construction

Answer 1

draw a line segment ab is 4.2 cm
draw 72 degrees with the help of rounder or compass
draw bc and join cd
draw o which lies on ab outside of quadrilateral

Answer 2

Given : ABCD in which AB=4.2cm, BC=4.5cm, CD=4 cm, DA=4.8 cm and angle A =72°

To Find :  construct Triangle

Solution:

Step 1  :  Draw a line segment AB = 4.2 cm

Step 2 :  Draw a ray at an angle of 72° at A on BA using protractor.

Step 3 :  Using compass width = 4.8 cm and taking A  as center cut the ray  drawn in previous step at D

Step 4 :  Using Compass width = 4.5 cm and taking B as center draw an arc

Step 5 : Using Compass width = 4 cm and taking D as center draw an arc intersecting arc drawn in previous step at C

Step 6 :  Join BC  &  CD.

Quadrilateral ABCD is constructed.

Learn More:

Construct quadrilateral PQRS such that PQ=PS=PR= 9cm ,QR ...

https://brainly.in/question/13885649

construct a quadrilateral pqrs in which sides PQ equal to 3 cm QR is ...

https://brainly.in/question/13262239