Question

ABCD is a cyclic quadrilateral.Find the angles of the cyclic quadrilateral.

Answer 1

3y-5-7x+5=180
3y-7x=180----------1

4y+20-4x=180
4y-4x=160
dividing each term by 4
y-x=40
y=40+x-------------2

putting 1 in2
3(40+x)-7x=180
120+3x-7x=180
-4x=60
x= -15

y=40-15
=25

so,
A=4*25 +20
=120
B=3*25-5
=70
C=-4*-15
=60
D=-7*-15+5
=110

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Answer 2

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