Math, asked by saksham00797, 10 months ago

ABCD is a cyclic quadrilateral. PQ is a tangent at B. If angle DBQ = 65 degrees, then angle BCD is equal to

Answers

Answered by ani284

7

Step-by-step explanation:

DBQ+BCD =180°

65°+BCD= 180°

BCD= 180°-65°

BCD= 115°

Answered by omakhani

2

answer

dbq+BCD = 180

65+bcd =180

bcd=180-65

bcd=115°

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