ABCD is a parallelogram and angle DAB = 60. If the bisectors AP and BP of angles A & B respectively meet at P on CD, Then proves that P is the midpt of CD.
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129
(After this)
Now, we got
DP=DA=CB=PC=PB
Here, DP=pc
Hence, proved
Hope it helped ^_^
Now, we got
DP=DA=CB=PC=PB
Here, DP=pc
Hence, proved
Hope it helped ^_^
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Answered by
54
the following attachment is the solution of your question
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