Question

ABCD is a parallelogram and e is the mid point of side Bc. de and ab on producing meet f .prove that af =2ab

Answer 1

ABCD is a parallelogram.
E is the midpoint of BC.
So, BE = CE. DE produced meets the AB produced at F.
Consider the triangles CDE and BFE.
BE = CE [Given]
∠CED = ∠BEF [Vertically opposite angles] ∠DCE = ∠FBE [Alternate angles]
∴ ΔCDE ≅ ΔBFE
So, CD = BF [CPCT]
But, CD = AB
,Therefore, AB = BF AF = AB + BF AF = AB + AB AF = 2AB Hence, proved.

Answer 2

Answer:

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