Question

ABCD is a parallelogram. Prove that ar(triangle AOD)=ar(triangle BOC)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The answer for the following question is given below .

Step-by-step explanation:

Given:

ABCD is a parallelogram  

In,(triangle AOD) and (triangle BOC)

∠AOD = ∠BOC (Vertical opposite angle are always equal)

AD = BC (parallel and equal sides of the parallelogram )

∠AOD = ∠BOC (AD║BC , Alternate angle are always equal)

Under ASA rule

(triangle AOD) ≅ (triangle BOC)

WE know that, if two triangles are congruent then their area is also equal.

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