ABCD is a parallelogram, X,Y,L and M are mid-points of AB,DC,AD and BC respectively,XY and LM intersect at O.show that AXOL is a parallelogram.
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Since ABCD is a ||gm and L,M are mid-points .
AL=BM=LD=MC so ALMB is ||gm bcoz LM||AB
||ly XY||AD
so AXOL ||gm
AL=BM=LD=MC so ALMB is ||gm bcoz LM||AB
||ly XY||AD
so AXOL ||gm
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