ABCD is a quadrilateral in which AB//DC and angleAD//BC find angle B , angle c and angle D
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hey mate
good morning
here's the answer
hope it helps you
good morning
here's the answer
hope it helps you
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azhagan2302:
sisy there is a wrong while subtracting...
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ABCD is a parallelogram.
hence opposite angles are equal......(1)
angle A + angle B = 180 (sum of angles of the corresponding sides of a parallelogram is 180°)
50° + B = 180°
B = 180°-50°
B = 130°
angle C = angle A.....from(1)
angle C = 50°
angle D = angle B.....from(1)
angle D = 130°
therefore angle,
B = 150°
C = 50°
D =150°
mate hope it helps you!
please mark me as the brainliest...
hence opposite angles are equal......(1)
angle A + angle B = 180 (sum of angles of the corresponding sides of a parallelogram is 180°)
50° + B = 180°
B = 180°-50°
B = 130°
angle C = angle A.....from(1)
angle C = 50°
angle D = angle B.....from(1)
angle D = 130°
therefore angle,
B = 150°
C = 50°
D =150°
mate hope it helps you!
please mark me as the brainliest...
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