ABCD is a quadrilateral in which AD =BC and angle DAB =angle CBA . prove that
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Answered by
15
Question :-
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see figure). Prove that
(i) ∆ABD ≅ ∆BAC
(ii) BD = AC
(iii) ∠ABD = ∠ BAC
Solution :-
In quadrilateral ACBD, we have
- AD = BC and
- ∠ DAB = ∠ CBA
(i) In ∆ ABC and ∆ BAC,
- AD = BC (Given)
- ∠DAB = ∠CBA (Given)
- AB = AB (Common)
∴ ∆ ABD ≅ ∆BAC (By SAS congruence)
(ii) Since ∆ABD ≅ ∆BAC
⇒ BD = AC [By C.P.C.T.]
(iii) Since ∆ABD ≅ ∆BAC
⇒ ∠ABD = ∠BAC [By C.P.C.T.]
hope it helps :)
Answered by
25
ABCD is a quadrilateral,
where AD=BC and ∠DAB=∠CBA
In △ABD and △BAC,
⇒ AD=BC [ Given ]
⇒ ∠DAB=∠CBA [ Given ]
⇒ AB=BA [ Common side ]
∴ △ABD≅△BAC [ SAS Congruence rule ]
∴ ∠ABD=∠BAC [ CPCT ]
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