Abcd is a quadrilateral with abc=73 degree,angle c =97 degree and angle d=120 degree. ae is parallel to dc. be is parallel to ad.find the angles of abe
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Step-by-step explanation:
Given AE is parallel to DC and BE is parallel to AD, ∠ ABC = 73°, C = 97°
To find : ∠ EBF
Since AE is parallel to DC
∴ 110° + ∠ DAE = 180°
(Co-interior ∠'s)
Also, ∠ BEA = ∠ DCF = 97° (Corresponding B ∠'s)
⇒ ∠ BEA = 97°
Now in Δ ABF,
∠ FAB + ∠ ABF + ∠ AFB = 180° (Angle Sum Property)
⇒ ∠ FAB + 73° + 97° = 180°
⇒ ∠ FAB = 180°-170°
⇒ ∠ FAB = 10°
Now, AD is parallel to BE (Given)
∴ ∠ DAB + ∠ ABE = 180° ( Co-interior angles)
⇒ ∠ DAF + ∠ FAB + ∠ ABF + ∠ EBF = 180°
⇒ 70° + 10° + 73° + ∠ EBF = 180°
∠ EBF = 180°- 153°
∠ EBF = 27°
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