ABCD is a quadrilateral with diagnol AC and BD intersecting at O. If ar(DOC) = ar(AOB). Show that /_BDA= /_DBC
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here area of triangle DOC=AR(triangle AOB
therefore, /_OAB=/_OCD
so, AB||CD
automatically
AD||BC,
therefore, /_BDA=/_ADO
because alternate angles are equal
therefore, /_OAB=/_OCD
so, AB||CD
automatically
AD||BC,
therefore, /_BDA=/_ADO
because alternate angles are equal
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gagannbohra:
thankyou so much
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