Question

ABCD is a rectangle, with AB = 4units and BC = 3 units. P and Q are midpoints of AD and DC respectively. Then the length of PQ is

Answer 1

Answer:

DP=1/2AD=1/2BC=3/2unit

DQ=1/2DC=1/2AB=2unit

as PDQ is a right angle triangle so,

PQ^2=PD^2+DQ^2

PQ^2=(9/4+4)sq unit=25/4sq unit

PQ=5/2unit=2.5unit