In the given figure, AB || CD then value of x is:
Answers
Given: AB || CD.
To find: The value of x.
Solution:
- Now we have given ang ABE = 75, ang BED = 30.
- Let the intersection point of BE and CD be O.
- Since AB || CD, so:
ang ABO + ang COB = 180 (interior angles)
ang COB = 180 - 75
ang COB = 105 = ang DOE (vertically opposite angles)
- In triangle DOE , we have:
ang DOE + ang OED + ang EDO = 180
ang EDO = 180 - 30 - 105
ang EDO = 45
Answer:
So the value of x is 45.
Given : AB || CD
To Find : value of x
Solution:
Properties of angles formed by transversal line with two parallel lines :
• Corresponding angles are congruent.
• Alternate angles are congruent. ( Interiors & Exterior both )
• Co-Interior angles are supplementary. ( adds up to 180°)
AB || CD and AC is transversal
Hence ∠FCD = 75° as corresponding angled
∠FCD is one of the exterior angle of triangle CEF
Exterior angle of triangle = sum of opposite two interior angles
=> ∠FCD = x + 30°
=> 75° = x + 30°
=> x = 45°
Value of x is 45°
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