Question

ABCD is a rhombus. If angle BCA=35° ,find angle ADC

Answer 1

As in rhombus the lines intersecting bisect it into two equal parts. so if angle BCA=35°. Then angle ADC= angle BCA
Therefore angle ADC= 35°

Answer 2

Answer:

Step-by-step explanation:

Angle BCA=35

Diagonals AC and BD intersect at M

Angle=CMB=90 as diagonals intersects at 90 degree in rhombus

Angle CBM=180-(90+35)=55 degree

Angle MDA =Angle CBM =55 degree (interior alternate angles)

Angle MAD=180-(90+55)=35 degree

In rhombus diagonals bisect at 90 degree

∴Angle CDB=Angle ADM =55 degree

∴Angle ADC=55+55=110 degree