Question

ABCD is a rhombus whose and side is 10cm and one of its diagonal is 16cm what is the area of rhombus

Answer 1

Step-by-step explanation:

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Answer 2

Solution:-

let, Rhombus ABCD.

given:-

•The sides of a rhombus are 10cm and one diagonal is 16cm .

let, DO = OB = 8 cm and

AO = OC = ?

1) we know diagonal of rhombus are equally bisect each other and they are perpendicular to each other.

2) All sodes of rhombus are equal.

so,

by Pythagoras theorem.

=> (AB)² = ( AO )² + ( OB )²

=> (10)² = (AO)² + (8)²

=> 100 = (AO)² + 64

=> 100 - 64 = (AO)²

=> 36 = (AO)²

i.e.

=> (AO)² = 36

=> AO = √36

=> AO = 6 cm

so, we know AO = OC = 6 cm

hence, AC = 12 cm

Area of rhombus = [(AC)×(BD)]/2

Area of rhombus = [ 12 × 16]/2

Area of rhombus = [192]/2

Area of rhombus= 99.84 cm²

Hence area of rhombus is

96 cm².

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