ABCD is a rhombus with AC = 16 cm and
AB=10cm
find the area of shombus ABCD
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Answered by
2
Answer:
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Step-by-step explanation:
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Answered by
1
Answer: 80 cm²
Step-by-step explanation:
Area of rhombus = (d₁ × d₂)/2
= (16 × 10)/2
= 160/2
= 80 cm²
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