ABCD is a rhombus with one diagonal equal to 18cm .& lengthof each side 15cm. Find the length of the other diagonal and area of the rhombus
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area of rhombus =1/2×d1×d2
(height ×side )
other diagonal will be
b^2=h^2-v^2
b^2= 15×15-9×9
=225-81
144 square root
12
orther diagonal will be 12
area of rhombus =1/2×18×12=216/6=108 cm ^2
(height ×side )
other diagonal will be
b^2=h^2-v^2
b^2= 15×15-9×9
=225-81
144 square root
12
orther diagonal will be 12
area of rhombus =1/2×18×12=216/6=108 cm ^2
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