Question

ABCD is a square prove that angle abc is an isosceles triangle also find angle X OD and angle X OC

Answer 1

diagonal of square are equal and bisect each other so OA = OB so ∆OAB is an isosceles∆. Since diagonal of square is also a single bisector.So, angle XDO = 1/2* angle D = 1/2*90° = 45°. So, in ∆XOD, angle XOD + angle XDO + angle DXO = 180 => angle XOD + 45 + 78 = 180 => angle XOD + 123 = 180 => angle XOD = 180 - 123 = 57°. Since diagonal of square bisect each other at 90°. So, angle DOC = 90° => angle XOD + angle XOC = angle DOC => 57 + angle XOC = 90 => angle XOC = 90 - 57 = 33°. So, angle XOD = 57° and angle XOC = 33°. Please please mark me as brainliest