ABCD is a trapezium in which AB||DC and its diagonals intersect each other at point ‘O’. Show that AO/BO = CO/DO.
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Answered by
238
Hey there!
Basic proportionality theorem :
If a line is drawn parallel to one side of the triangle , Then the other sides are divided in the same ratio.
Here, We prove that
In trapezium ABCD , AO/BO = CO/DO
using the Basic proportionality theorem.
We constructed OX || AB and proceeded with the problem.
Check out the attachment for detailed explanation.
Hope helped!
Basic proportionality theorem :
If a line is drawn parallel to one side of the triangle , Then the other sides are divided in the same ratio.
Here, We prove that
In trapezium ABCD , AO/BO = CO/DO
using the Basic proportionality theorem.
We constructed OX || AB and proceeded with the problem.
Check out the attachment for detailed explanation.
Hope helped!
Attachments:
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92
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