Abcd is a trapezium in which ab dc and p and q are points on ad and bc, respectively such that pq dc. If pd = 18 cm, bq = 35 cm and qc = 15 cm, find ad.
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given:- abcd is a trepezium in which ad||dc & p q are points on ad & bc resp. s.t pc||dc
also pd=18cm
bq=35cm & pc=15 cm
to find:-now, bc=50cm
as ab||dc & pq||dc
therefore ab||pq||dc
so ap/pd=bq/qc
ap/18cm=35/15cm
ap/18cm=2.33cm
ap=2.33×18cm
ap =41.94cm
as ad= ap+pd
ad=41.94+18cm
ad=59.94cm
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Answer:
59.94
Step-by-step explanation:
Given:- ABCD is a trepezium in which AD||DC & P&Q are points on AD & BC resp. such that PC||DC
also PD=18cm
BQ=35cm & PC=15 cm
Solution:-BC=50cm
As AB||DC & PQ||DC
Therefore AB||PQ||DC
Hence, AP/PD=BQ/QC
AP/18cm=35/15cm
AP/18cm=2.33cm
AP=2.33×18cm
AP =41.94cm
Now, Since AD= AP+PD
AD=41.94+18cm
AD=59.94cm
Hope this helps
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