For what value of k,the following system of equations have
(i) a unique solution?
(ii) no solution
2x+Ky=1,3x-5y=7.
Answers
Answered by
3
Hi Friend !!!
Here is ur answer !!!
I) unique solution :
2/3 ≠k/-5
k ≠-10/3
II) no solution :
2/3 = k/-5
k = -10/3
Hope it helps u :-)
Here is ur answer !!!
I) unique solution :
2/3 ≠k/-5
k ≠-10/3
II) no solution :
2/3 = k/-5
k = -10/3
Hope it helps u :-)
mohammedfaizan258:
hey can you solve one more question for me
ok
this is the question
Solve graphically the following system of linear equations:
2x-y=2
4x-y=8
Also,finds the coordinates of the points where the lines meet the axis of x.
2x-y=2
4x-y=8
Also,finds the coordinates of the points where the lines meet the axis of x.
it's graphically
yes
solve fast
it's graphically so I cant
ok
^_^
Answered by
1
Answer:
We have been given two equations 2x + ky = 11 & 3x - 5y = 7.
∴ We have to find a unique Solution for system of equation.
(i)For Unique solution, We have:-
- a1/a2 ≠ b1/b2
Here, a1 = 2 ,b1 = k & a2= 3 , b2 = 5
Substitute obtained values in Equation:
⇒ a1/a2 ≠ b1/b2
⇒ 2/3 ≠ k/-5
⇒ 3k≠ 10
∴ k = -10/3
(ii)For No Solution, We have:-
- a1/a2 = b1/b2 ≠ c1/c2
Here, a1 = 2 ,b1 = k & a2= 3 , b2 = - 5 & c1 = 11 , c2 = 7
Substitute obtained values in Equation:
⇒a1/a2 = b1/b2 ≠ c1/c2
⇒ 2/3 = k/-5 ≠ 11/7
⇒ 2/3 = k/-5
⇒ 3k = -10
⇒ k = -10/3
∴ k = -10/3
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