ABCD is a trapezium of area 91cm sq CD is parallel to AB CD is longer than AB by 8cm.If the distance between AB and CD is 7cm,find AB and CD
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38
Here you go! Hope this is the right one.
Area of a trapezoid/trapezium is the height multiplied by the sum of parallel sides and this whole equation divided by 2.
Area of a trapezoid/trapezium is the height multiplied by the sum of parallel sides and this whole equation divided by 2.
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shubham340:
91cm sq =3.5(2x+8) ke baad 7x==91-28 me 7x kaise aaya
Sorry....i should've done it step by step. It goes like this.... 3.5×2 is 7 and 3.5×8 is 28. Now we move the unknown value to one side which results in 7x=91-28. The sign changes as it moves on the other side.
imagine it as 91=7x+28....91-28=7x
i hope i have cleared your dou t
thanks
not in proper way
sry bro i didn't like bro
Answered by
21
Let Ab be x
Let CD be x+8
According to question.
Area = 1/2 ×(sum of // sides)×h
91=1/2×(2x + 8)×7
91×2÷7=2x +8
182÷7=2x+8
26=2x+8
26-8=2x
18=2x
18÷2=x
9=x
AB = 9 cm
CD= x+8
=9+8
= 17cm
Step-by-step explanation:
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