Abdul travelled 300 km by train and 200 km by bus in 5 h 30 min. If he had travelled 260 km by train and 240 km by bus he would have taken 6 min. Longer find speed of train and bus
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1st case :
distance travelled by train = 300km
and by taxi = 200km
Let speed of train be x km/hr and that of taxi be y km/hr.
so, time taken by train = d/s time taken by taxi = d/s
= 300/x = 200/y
total time taken = 5hrs 30 mins = 5 1/2 hrs
so, 300/x +200/y = 5 1/2 by solving we get : 600y + 400x = 11xy..........1
2nd case :
distance travelled by train = 260 km and by taxi = 240 km
here also speed of train be x km/hr and of taxi be y km/hr
Then time = d/s
train time= 260/x hr of taxi = 240/y hr
combiningly,total time =
260/x + 240/y = 5hrs 36 mins
=> or 260/x + 240/y = 5 3/5 on solving we get,
1300y + 1200x = 28xy...............2
eq 1 × 3 = 1800y + 1200x = 33xy
on solving 1 and 2 we get:
x=100 km/hr
y= 80 km/hr
Hope This helps :)
distance travelled by train = 300km
and by taxi = 200km
Let speed of train be x km/hr and that of taxi be y km/hr.
so, time taken by train = d/s time taken by taxi = d/s
= 300/x = 200/y
total time taken = 5hrs 30 mins = 5 1/2 hrs
so, 300/x +200/y = 5 1/2 by solving we get : 600y + 400x = 11xy..........1
2nd case :
distance travelled by train = 260 km and by taxi = 240 km
here also speed of train be x km/hr and of taxi be y km/hr
Then time = d/s
train time= 260/x hr of taxi = 240/y hr
combiningly,total time =
260/x + 240/y = 5hrs 36 mins
=> or 260/x + 240/y = 5 3/5 on solving we get,
1300y + 1200x = 28xy...............2
eq 1 × 3 = 1800y + 1200x = 33xy
on solving 1 and 2 we get:
x=100 km/hr
y= 80 km/hr
Hope This helps :)
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