Question

Abid has worked for the same employer for 5 years.
His current salary is $73,500 which is 122.5% of her starting salary.
What was his starting salary?

Answer 1

salary at the middle of every year starting from the first year. If his monthly salary was Rs. 78000 at the end of 6 years of service and Rs. 84000 at the end of 12 years of service, find hi

Let initial monthly salary be Rs. x and increment be Rs. y.

Therefore, salary of first 6 months = Rs. x

Salary of next 1 year = Rs. 12(x+y).

Salary of next 1 year =12(x+2y)

Again, salary for next 1 year =12(x+5y)

Therefore, salary of last 6 months =6(x+6y)

Monthly salary of last month =x+6y

⇒x+6y=78000 ....(1)

Similarly, salary at the end of 12 years is x+12y.

⇒x+12y=84000 ....(2)

Subtracting equations (1) and (2), we get

6y=6000

⇒y=1000

Put this value in equation (1), we get

x+6(1000)=78000

⇒x=78000−6000

⇒y=72000

Thus, monthly salary is Rs. 72000 and annual increment is Rs. 1000.