consider an elastic spring of negligible mass with its own one end attached to a block of masss m which can slide over a smooth horizontal surface. the position n= 0 osvthe ewuilibriloum position
1. if we stretched the mass and release the mass it wants to be at ?
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Answer:
Maximum speed is at mean position(equilibrium). F=kx
x=
k
F
W
F
+W
sp
=ΔKE
F(x)−
2
1
kx
2
=
2
1
mv
2
−0
F(
k
F
)−
2
1
k(
k
F
)
2
=
2
1
mv
2
⇒V
max
=
mk
F
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