Question

ac current of 2 amp flows in a wire of resistance 10 ohm fir 7 minutes. how much heat is produced​

Answer 1

Answer:-

H = 16.8 kJ

Given :-

I = 2 A

R = 10 $\Omega$

t = 7 minutes

→ 7 × 60

→ 420 s

To find :-

The heat produced in the conductor.

Solution:-

By joule's Law of heating the heat produced in a conductor is given by :-

$\huge \boxed{ H = I^2 R T}$

Now ,

Put the value

→$H = 2^2 \times 10 \times 420$

→$H = 4 \times 4200$

→$H = 16800 J$

1 KJ = 1000J

=16800/1000

= 16.8 kJ

hence,

The heat produced in the conductor is 16.8 kJ.