Question

acceleration of a body is given by the equation (4-3v)m/s²speed v is in m/s and t is in second if initial velocity is in zero then terminal velocity of the body is​

Answer 1

Explanation:

Let,

The given equation of acceleration of a body, V= (4-3v)m/s^2

Initial Velocity, u= 0 m/s^2

We know, at terminal velocity, V=0

So, 4-3v=0

√ 3v= 4

√ v= 4/3

√ v= 1.33

Terminal velocity 1.33 m/s^2. (Ans)

Answer 2

Answer:4/3m/s

Explanation:guys in this question the terminal velocity have to be found at which the acceleration becomes zero

Therefore

a=4-3v

a=0

4=3v

v=4/3m/s

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