Question

According to equation c6h6 + 15/2o2 = 3h2o + 6co2 ∆h = -3264.4 kj/mol the energy evolved when 7.8 g of benzene is burnt in air will be

Answer 1

Answer: 32.44 kJ of energy will evolve when 7.8 g of benzene is burnt in the air.

Explanation:

$C_6H_6+\frac{15}{2}O_2\rightarrow 3H_2O+6CO_2,\Delta H=-324.4 kJ/mol$

Moles of benzene =$\frac{\text{mass of benzene}}{\text{molar mass of benzene}}=\frac{7.8 g}{78 g/mol}=0.1 mol$

According reaction, for 1 mole of benzene -324.4 kJ of energy is reevloved

Then for 0.1 mole of benzene will give: $-324.4 kJ/mol\times 0.1 mol=-32.44 kJ$

Negative sign means energy is released.

-32.44 kJ of energy will evolve when 7.8 g of benzene is burnt in the air.

Answer 2

Answer: 32.44 kJ of energy will evolve when 7.8 g of benzene is burnt in the air.

Explanation:

Moles of benzene =

According reaction, for 1 mole of benzene -324.4 kJ of energy is reevloved

Then for 0.1 mole of benzene will give:

Negative sign means energy is released.

-32.44 kJ of energy will evolve when 7.8 g of benzene is burnt in the air.

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