One end of a copper rod of length 1.0 m and area of cross-section 103 m2 is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is 92 cal/m-sc and the latent heat of ice is 8 104 cal kg, then the amount of ice which will melt in one minute is
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length of copper rod , dx = 1m
area of cross sectional area , A = 10^-3 m²
coefficient of thermal conductivity of copper , k = 92 cal/m/s
latent heat of ice, L = 8 × 10⁴ cal/Kg
here, One end of a copper rod of length 1.0 m and area of cross-section 10³ m³ is immersed in boiling water and the other end in ice.
heat generated per minute , H = kAdT/dx × t
= 92 × 10^-³ × (100 - 0)/1 × 60 cal
= 92 × 10 × 60 cal
= 55200 cal
heat required to melt the ice of mass m = mL
m × 8 × 104 = 55200
m = 55200/8 × 10⁴ = 0.69kg
area of cross sectional area , A = 10^-3 m²
coefficient of thermal conductivity of copper , k = 92 cal/m/s
latent heat of ice, L = 8 × 10⁴ cal/Kg
here, One end of a copper rod of length 1.0 m and area of cross-section 10³ m³ is immersed in boiling water and the other end in ice.
heat generated per minute , H = kAdT/dx × t
= 92 × 10^-³ × (100 - 0)/1 × 60 cal
= 92 × 10 × 60 cal
= 55200 cal
heat required to melt the ice of mass m = mL
m × 8 × 104 = 55200
m = 55200/8 × 10⁴ = 0.69kg
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