Question

According to heisenberg's uncertainty principle, the product of uncertainties in position and velocities for an electron of mass 9.1 × 10–31 kg is

Answer 1

according to Heisenberg's uncertainty principle
del x . del p > h/4 pi

del p = m . del v
so,
del x. m. del v > h/4 pi
so,
del x. del v > h/( 4 pi.m)

so putting values of h, pi, m (mass of electron)
we can get the minimum uncertainty in product of position and velocity