Question

ACETYLENE CAN BE PREPARED FROM CALCIUM CARBONATE BY A SERIES OF REACTIONS.THE MASS OF 80% CALCIUM CARBONATE REQUIRED TO PREPARE 2MOLES OF ACETYLENE IS?​

Answer 1

Answer:

250g

c2h2 molecular weight is 26

caco3 molecular weight is 100

80% caco3

2 moles c2H2

(80/100÷2×26)100

13/5×100

260g

approx(250)g

Answer 2

Answer:

250 gm

Explanation:

the equations are

CaCO3 ⇒ CaO +CO2

CaO + 3C ⇒ CaC2+ CO

CaC2 + 2H2O ⇒ Ca(OH)2 +C2H2(ACETYLENE)

On rearranging the equations we get

2H2O + CaCO3 +3C ⇒ CO +Ca(OH)2 +C2H2 +CO2

∴ 1 mole of CaCO3 produces 1 mole of C2H2

2 moles of C2H2 means 2 moles of CaCO3

2 moles of CaCO3 weighs 200 gm of 100% pure CaCO

but here

80%(total mass of CaCO3) = 200

(80÷100) × X = 200

X = (200× 100)÷80

X = 250 gm