AD is a diameter of a circle and AB is a chord . if AB= 30 cm and it's perpendicular distance from the centre of the circle is 8 cm , then what is the length of the diameter AD
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in the figure
OX⏊AB
X is the mid point of AB[∵⏊ from the centre to any chord of a circle bisects the chord]
AX=BX=1/2AB=15cm
OX= 8cm
AO=√(AX²+OX²)
AO=√(225+64)
AO=±17
AO = 17 [∵length can never be negetive]
r= 17 cm
d=2r=34cm
AD = 34cm
OX⏊AB
X is the mid point of AB[∵⏊ from the centre to any chord of a circle bisects the chord]
AX=BX=1/2AB=15cm
OX= 8cm
AO=√(AX²+OX²)
AO=√(225+64)
AO=±17
AO = 17 [∵length can never be negetive]
r= 17 cm
d=2r=34cm
AD = 34cm
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