Question

pls solve this i will mark as brainlist no spam answers else report solve it is very easy

Answer 1

Answer:

PR = 26 cm.

Step-by-step explanation:

Hey!

We see pq is tangent.

So triangle poq is rt angled.

(tangent forms right angle at the point of contact with the radius of circle)

So,

We get :

Po^2 = 3^2 + 4^2 (Pythagoras th.)

(PQO is rt angled triangle)

Po^2 = 9 + 16 = 25

➡️ PO = 5 cm

Similarly,

SO'R is rt angled triangle

So,

5^2 + 12 ^2 = RO'^2

25 + 144 = RO'^2

RO'^2 = 169

➡️ RO' = 13 cm

Let point of intersection of both circles be X.

Then,

➡️ OX = 3 cm (radius)

➡️ O'X = 5 cm (radius)

We see,

✔️PR = PO + OX + O'X + O'R

✔️PR = 5 + 3 + 5 + 13 CM

✔️PR = 26 cm

Answer 2

Step-by-step explanation:

Here is your answer

Hope it helps you.