Question

AD is a median of ∆ABC. if area of ∆ABC=44cm,find the area of ∆ADC.

Answer 1

we know that a median of triangle separates the triangle to two equal halves.
the whole triangle - ABC is divided to two halves.

halves - ∆ADC  and ∆ADB
thus ∆ADC = ∆ADB ----------------1
area of (∆ADC + ∆ADB ) = 44
with 1,
2 * ∆ADC =44
∆ADC = 22 cm^2

thus, area of ∆ADC = 22cm^2


hope it helps!!!!

Answer 2

Hi there !!

In the figure :

ABC is a triangle.
AD is the median

We know that a median of a triangle  , divided the triangles into two congruent triangles [ triangles equal in area ]

AD divides the ΔABC  into two triangles ADC and ADB , which will be of equal area.

ar (ΔADC) = ar (ΔADB)                    ........... (1)

we know that

 ar(ΔABC ) = 44 cm²

ar(ABC ) = ar (ΔADC) + ar (ΔADB)

44 cm² = ar (ΔADC) + ar (ΔADB)

44 cm²  = 2 ar (ΔADC)                      [from (1) ]

∴
 ar (ΔADC)   = 1/2 ar(ΔABC )
                     = 1/2 × 44
                     = 22 cm²