Question

add 5/3 To the difference of 7/3 and 7/6.

Answer 1

$\frac{5}{3} + ( \frac{7}{3} - \frac{7}{6} ) \\ \\ = \frac{5}{3} + ( \frac{14 - 7}{6} ) \\ \\ = \frac{5}{ 3} + \frac{7}{6} \\ \\ = \frac{10 + 7}{6} \\ \\ = \frac{17}{6}$

Answer 2

Solution :- 

Difference of 7/3 and 7/6 

= $\frac{7}{3} - \frac{7}{6}$ 

= $\frac{14-7}{6}$

= $\frac{7}{6}$


Adding 5/3 

= $\frac{7}{6} + \frac{5}{3}$

= $\frac{7+10}{6}$

= $\frac{17}{6}$


i hope this will help you



-by ABHAY