Add a+b-1,- b- a+ 1, 1 -2
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Answer:
LHS
= (A+A'B)'
= (A'.(A'B)')
= (A'.(A+B')) // again applied de-morgan's law in previous step
= (A'.A+A'B')
= A'B'
also apply De-morgans on RHS
(A+B)'
= A'B'
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