Question

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Find the value of x for which the numbers (5x+2),(4x-1) and (x+2) are in AP.

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Answer 1

Given that (5x + 2),(4x - 1) and (x + 2) are in AP.

= > (4x - 1) - (5x + 2) = (x + 2) - (4x - 1)

= > 4x - 1 - 5x - 2 = x + 2 - 4x + 1

= > -x - 3 = 3 - 3x

= > 2x = 6

= > x = 3.

Therefore, the value of x = 3.

Hope this helps!

Answer 2

Hi,

Please see the attached file!!



Thanks