Question

ahoy!!

differentiate w.r.t x

$(1 + {x}^{2} )log \: 2x$
thanks!!

Answer 1

Hi,

Here is your answer,

y = (1+x)²log2x

Differentiate with respect to x

→ dy/dx = (1+x)²1/2x × 2(1) + log2x × (0 + 2x)  { On Cancelling } we get,

→ dy/dx = 1 +x²/x + 2x.log2x

→ 1 + x² + 2x² log2x/x

         → dy/dx = 1 + x² (1+log2x)/x     { FINAL ANSWER }


Hope it helps you !

Answer 2

${ \underline { \bf Namaste ! }} \\ \\ \bf \: See \: the \: attached \: picture \\ \\ \bf I \: have \: solved \: this \: by \: "Chain \: rule" \\ \\ \bf \: Cheers : )$