ahoy!!
differentiate w.r.t x
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hrushi2000:
can you tell me in which class you are or which book are you referring to.
class 11th
random questions on differentiation
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Hi,
Here is your answer,
y = (1+x)²log2x
Differentiate with respect to x
→ dy/dx = (1+x)²1/2x × 2(1) + log2x × (0 + 2x) { On Cancelling } we get,
→ dy/dx = 1 +x²/x + 2x.log2x
→ 1 + x² + 2x² log2x/x
→ dy/dx = 1 + x² (1+log2x)/x { FINAL ANSWER }
Hope it helps you !
Here is your answer,
y = (1+x)²log2x
Differentiate with respect to x
→ dy/dx = (1+x)²1/2x × 2(1) + log2x × (0 + 2x) { On Cancelling } we get,
→ dy/dx = 1 +x²/x + 2x.log2x
→ 1 + x² + 2x² log2x/x
→ dy/dx = 1 + x² (1+log2x)/x { FINAL ANSWER }
Hope it helps you !
I hope my answer is correct.
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