air contains 21% of oxygen by volume find the volume of oxygen in a room of dimension for 4m by 5m by 3m
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Answer:
12.6L
Step-by-step explanation:
the question says that in 100L of air 21L of oxygen is present so in 5×4×3 = 60L of air in the room
100L of air-----》21L of oxygen
60L of air------》 x L of oxygen
so, (21*60)÷100 = 12.6L
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