Question

air contains 21% of oxygen by volume find the volume of oxygen in a room of dimension for 4m by 5m by 3m​

Answer 1

Answer:

12.6L

Step-by-step explanation:

the question says that in 100L of air 21L of oxygen is present so in 5×4×3 = 60L of air in the room

100L of air-----》21L of oxygen

60L of air------》 x L of oxygen

so, (21*60)÷100 = 12.6L