Question

Ajay covers certain distance with his own speed but when he really reduced speed by 10 kilometre per hour is time duration for the journey increases by 40 hours with if increases speed but 5 kilometre per hour from this original speed he takes 10 hours less than the original type take and find the distance covered by him.brinly ​

Answer 1

Answer:

the original speed of Ajay be x km/hr and distance be d km.

Condition first

d/(x – 10) – d/x = 40

⇒ d [x – x + 10] / [x (x – 10)] = 40

⇒ 10d = 40 x (x – 10)

⇒ d = 4x (x – 10) ---(1)

Condition second

d/x – d/(x + 5) = 10

⇒ d [x + 5 – x]/[x (x + 5)] = 10

⇒ 5d = 10x (x + 5)

⇒ d = 2x (x + 5) ---(2)

From equation (1) and equation (2)

4x (x – 10) = 2x (x + 5)

⇒ 2 (x – 10) = (x + 5)

⇒ 2x – 20 = x + 5

⇒ 2x – x = 20 + 5

⇒ x = 25

From equation (2)

d = 2 × 25 (25 + 5)

⇒ d = 50 × 30

⇒ d = 1500 km

∴ The distance covered by Ajay is 1500 km.