Math, asked by sathish3k, 11 months ago

Ajay distributes some pebbles among his friends. By giving each of them either 8 or 9 0r 10, he is left with no pebbles. What is the least number of pebbles he must have?

Answers

Answered by anshulagarwal508
8

Answer:

Least no of pebbles he must have are

LCM of 8,9 and 10

=360

Hence ajay has 360 pebbles

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Step-by-step explanation:

Answered by Anonymous
10

answer :

360 pebbles

Step-by-step explanation:

least number of pebbles he must have

= LCM of 8,9&10

LCM of 8 , 9 & 10 = 360

he must have 360 pebbles

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