Ajay is 36 years older than his son. After 10 years, Ajay will be three times as old as his son. Find their present ages.
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Answered by
6
Answer:
Let the age of man be x
and the age of his son be y
According to the question:
After 6 years :
(x+6)=3(y+6)
⇒x−3y=12⟶(i)
Three years ago :
x−3=9(y−3)
⇒x−3=9y−27
⇒x−9y=−24⟶(ii)
Solving (i) and (ii),
6y=36
⇒y=6
Putting value of y in equation (i),
x−3xy=12
∴x=12+18
x=30
∴ Age of man =30 years.
Age of son =6 years.
Answered by
0
Answer:
Ajay will be 30 and his son will be 6.
:)
Step-by-step explanation:
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