Ajay starts from his house to his office by his car which is 15km away at an average speed of 45 km per hour . On the way back he takes a route longer by 5 km since there is heavy traffic on the regular route . If he reaches home in the same time as the time he took to reach office in the morning. find his speed on the return journey
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Solution :
in morning when he went office from home
speed of car 45 km/hr
then time taken = distance/speed
=> 15/45
=> ⅓ hour
=> 20 minutes
at the evening when returned from office to home
the travel 20km and time taken 20 minutes ⅓ hour
then speed of car when he returned
=> 20/⅓
=> 20 x 3
=> 60km
=> 60km/hr his speed on the return journey
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