Question

Al₂O₃ is reduced by electrolysis at low potentials and high
currents. If 4.0 × 10⁴ amperes of current is passed through
molten Al₂O₃ for 6 hours, what mass of aluminium is
produced? (Assume 100% current efficiency. At. mass of
Al = 27 g mol⁻¹)
(a) 8.1 × 10⁴ g (b) 2.4 × 10⁵ g
(c) 1.3 × 10⁴ g (d) 9.0 × 10³ g

Answer 1

The mass of aluminium produced is W = 8.1 x 10^4 g

Option (A) is correct.

Explanation:

Applying E = Z x 96500

27 / 3 = Z x 96500

Z = 9 / 96500

Now applying the formula:

W = Z x I x t

W = 9 / 96500 x 4 x 10^4 x 6 x 60 x 60

W = 8.1 x 10^4 g

Thus the mass of aluminium produced is W = 8.1 x 10^4 g

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