Science, asked by mobarak3486, 1 year ago

Alkyl halides are generally not prepared in laboratory by free radical halogenations of alkanes.

Answers

Answered by yuvrajkarle
10
Tetramethyl lead: 4CH3Cl + Na4Pb -------------> (CH3)4 Pb + 4NaCl Ttraethyl lead : 4CH3CH2---Cl +Na4Pb ---------------> (CH3CH2)4Pb +4NaCl

Answered by gratefuljarette
62

'Alkyl halides' are generally not prepared in laboratories by 'free radical halogenation' of alkanes because, the presence of different types of hydrogen atoms in alkanes.

EXPLANATION:

These hydrogen atoms make it difficult to break the bond and separate the alkanes in laboratories.

In the free radical halogenation of alkanes, more than one hydrogen atom gets replaced that results in the poly-halogen compounds formation which increase the complexity of the process and mixture cannot be easily 'separated'.  

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